24t=2.1t^2

Solution for 24t=2.1t^2 equation:

24t=2.1t^2

We move all terms to the left:

24t-(2.1t^2)=0

We get rid of parentheses

-2.1t^2+24t=0

a = -2.1; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-2.1)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-2.1}=\frac{-48}{-4.2}
=11+1/2.33333333333
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-2.1}=\frac{0}{-4.2}
=0
$